Using '0' as the padding results in the first exception I describe. There is a trial version of Mathematica in the Wolfram website, which can be downloaded for free with a license valid for 15 days.
If it does require padding, what do I pad with? I tried this: final decrypted = crypt(16(cipher.padRight(16, null)), iv: iv) īut I get the following exception: E/flutter (19095): FormatException: Invalid radix-16 number (at character 1) I thought AES CTR mode did not require any padding. Mathematica 12.2 Download (Free trial) - Mathematica.exe. Here is my code: final encrypter = encrypt.Encrypter(encrypt.AES(key, mode: )) įinal decrypted = crypt(16(cipher), iv: iv) Ĭipher is hexadecimal string of length 10. Wolfram Mathematica 12.2.0 5KPlayer for Mac 5KPlayer is a new-style free media player for Mac. I get this exception when I use Dart's encrypt package to decrypt something using AES CTR mode: E/flutter (19095): Invalid argument(s): Input data length must be a multiple of cipher's block sizeĮ/flutter (19095): #0 PaddedBlockCipherImpl.process (package:pointycastle/padded_block_cipher/padded_block_cipher_impl.dart:55:9)Į/flutter (19095): #1 AES.decrypt (package:encrypt/src/algorithms/aes.dart:38:20)
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